\frac{x^3}{2}-\frac{x^2}{3}=\frac{x}{6}
\frac{3x^3-2x^2}{6}=\frac{x}{6} |*6
3x^3-2x^2=x
3x^3-2x^2-x=0
x(3x^2-2x-1)=0
x=0
lub
3x^2-2x-1=0
a=3, b=-2, c=-1
\Delta=b^2-4ac=(-2)^2-4*3*(-1)=4+12=16
\sqrt\Delta=4
x_1=\frac{-b-\sqrt\Delta}{2a}=\frac{2-4}{2*3}=-\frac{2}{6}=-\frac{1}{3}
x_2=\frac{-b+\sqrt\Delta}{2a}=\frac{2+4}{6}=\frac{6}{6}=1
x_1=-\frac{1}{3} , x_2=1 , x_3=0