\frac{6*^{\sqrt3}*3^{-\sqrt3}}{2^{\sqrt3}}
źródło:
\frac{6*^{\sqrt3}*3^{-\sqrt3}}{2^{\sqrt3}}=\frac{2^{\sqrt3}*3^{\sqrt3}*3^{-\sqrt3}}{2^{\sqrt3}}=
=3^0=1