Zadanie 3
(2^{\sqrt2-\sqrt5})^{\sqrt5+\sqrt2}=(2^{\sqrt2-\sqrt5})^{\sqrt2+\sqrt5}=2^{(\sqrt2)^2-(\sqrt5)^2=2^{2-5}}=2^{-3} odpowiedź A
Zadanie 8
\frac{(\frac{1}{8})^{-3}*16^{-2}}{4*\sqrt{2^4}}=\frac{((\frac{1}{2})^3)^{-3}*(2^4)^{-2}}{4*\sqrt{16}}=\frac{(\frac{1}{2})^{-9}*2^{-8}}{16}=
\frac{2^9*2^{-8}}{2^4}=2^{1-4}=2^{-3}=(\frac{1}{2})^3=\frac{1}{8}