Zadanie Liczba ((1/(3+ 2√2)−(3+2√2))^2 jest równa?
źródło:
[\frac{1}{3+2\sqrt2}-(3+2\sqrt2)]^2=
(\frac{3-2\sqrt2}{(3+2\sqrt2)(3-2\sqrt2)}-3-2\sqrt2)^2=
(\frac{3-2\sqrt2}{9-4*2}-3-2\sqrt2)^2=
(\frac{3-2\sqrt2}{1}-3-2\sqrt2)^2=
(3-2\sqrt2-3-2\sqrt2)^2=
(-4\sqrt2)^2=16*2=32