a= \sqrt{4^2 + 3^2} * 5^2 + (-\frac{3}{2})^2=\sqrt{25}*25+\frac{9}{4}=5*25+2\frac{1}{4}=125+2,25=127,25
b= \frac{(3+2\sqrt{3})^2 - (2 -3\sqrt{3})^2 +10}{(1+\sqrt{3})^2 - (\sqrt{3} -1)^2 + 2\sqrt{3}}=\frac{9+12\sqrt3+4*3-(4-12\sqrt3+9*3)+10}{1+2\sqrt3+3-(3-2\sqrt3+1)+2\sqrt3}=
=\frac{21+12\sqrt3-4+12\sqrt3-27+10}{4+2\sqrt3-3+2\sqrt3-1+2\sqrt3}=\frac{24\sqrt3}{6\sqrt3}=\frac{6\sqrt3*4}{6\sqrt3}=4
c= \frac{27^3 * 3^7 * (-3)^0}{9^4 * 3^8}=\frac{(3^3)^3*3^{7+0}}{(3^2)^4*3^8}=\frac{3^{9+7}}{3^{8+8}}=\frac{3^{16}}{3^{16}}=1
\frac{a}{b+c}*100\%=\frac{127,25}{4+1}*100\%=\frac{127,25}{5}*100\%=\frac{12725}{5}\%=2545\% <-- odpowiedź