c)
\frac{4^{2+\sqrt2}}{\sqrt2^{\sqrt32}}=\frac{(2^2)^{2+\sqrt2}}{(2^{\frac{1}{2}})^{\sqrt{16*2}}}=\frac{2^{4+2\sqrt2}}{(2^{\frac{1}{2}})^{4\sqrt2}}=\frac{2^4*2^{2\sqrt2}}{2^{2\sqrt2}}=2^4=16
a)
(17^{\sqrt3-\sqrt2})^{\sqrt3+\sqrt2}=17^{(\sqrt3)^2-(\sqrt2)^2}=17^{3-2}=17
wzór skróconego mnożenia
(a-b)(a+b)=a^2-b^2