\frac{x-2m}{3x-2}= \frac{2}{x} założenie: 3x-2\ne0 i x\ne0 , D=R-\{\frac{2}{3},0\}
x(x-2m)=2(3x-2)
x^2-2mx=6x-4
x^2-2mx-6x-4=0
x^2-(2m+6)x+4=0
a=1, b=2m+6, c=4
\Delta>0
(2m+6)^2-4*1*4>0
4m^2+24m+36-16>0
4m^2+24m+20>0|:4
m^2+6m+5>0
m^2+5m+m+5>0
m(m+5)+(m+5)>0
(m+5)(m+1)>0
m=-5\vee m=-1
m\in (-\infty;-5)\cu (-1;+\infty)