a=h=3cm
z twierdzenia Pitagorasa
1)
c^2=a^2+a^2
c^2=2a^2
2)
(\frac{1}{2}c)^2+h^2=a^2
\frac{1}{4}c^2+3^2=a^2
\frac{1}{\not4^2}*\not2^1a^2+9=a^2
\frac{1}{2}a^2-a^2=-9|*2
a^2-2a^2=18
-a^2=-18|*(-1)
a^2=18 => a=\sqrt{18}=\sqrt{9*2}=3\sqrt2
c^2=2a^2
c^2=2*18
c=\sqrt{36}
c=6(cm)
r=\frac{a+b-c}{2}
a=b
r=\frac{2a-c}{2}=\frac{2*3\sqrt2-6}{2}=3\sqrt2-3=3(\sqrt2-1)(cm) <-- odpowiedź