Zadanie 8
\frac{(2-\not18^3*\frac{1}{\not24^4})^2}{0,75+2\frac{3}{8}}=\frac{(2-\frac{3}{4})^2}{\frac{3}{4}+\frac{19}{8}}=\frac{(1\frac{1}{4})^2}{\frac{6}{8}+\frac{19}{8}}=
=\frac{(\frac{5}{4})^2}{\frac{25}{8}}=\frac{\frac{25}{16}}{\frac{25}{8}}=\frac{25}{16}*\frac{8}{25}=\frac{1}{2}
Zadanie 9
(\frac{3}{4})^2....(\frac{2}{3})^3
\frac{9}{16}....\frac{8}{27}
wspólny mianownik 243
\frac{243}{432}>\frac{128}{243}
(\frac{3}{4})^2>(\frac{2}{3})^3