(x^2-16)(4x-1)>0
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(x^2-16)(4x-1)=0
(x-4)(x+4)(4x-1)=0
x-4=0\vee x+4=0\vee 4x-1=0
x=4\vee x=-4\vee 4x=1
x_1=-4 , x_2=\frac{1}{4} , x_3=4
x\in (-4;\frac{1}{4})\cup (4;+\infty)
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