Zadanie 1
a=5
b=6
\alpha=30^0
\frac{a}{sin30^0}=\frac{b}{sin\beta}
\frac{5}{\frac{1}{2}}=\frac{6}{sin\beta}
5*sin\beta=6*\frac{1}{2}
5sin\beta=3|:5
sin\beta=\frac{3}{5}=0,6
\beta\approx 37^0 II kąt
\gamma=180^0-30^0-37^0=113^0 III kąt
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\frac{c}{sin\gamma}=\frac{a}{sin\alpha} , …sin113^0=sin(180^0-113^0)=sin67^0
\frac{c}{sin67^0}=\frac{5}{sin30^0}
\frac{c}{0,9205}=\frac{5}{\frac{1}{2}}
\frac{c}{0,9205}=\frac{10}{1}
c=10*0,9205
c\approx 9,2