\frac{(8^{\sqrt2})^{\frac{\sqrt2}{2}}:16^{\frac{1}{2}}}{(2^{\sqrt2-\sqrt3})^{\sqrt2+\sqrt3}}
źródło:
\frac{(8^{\sqrt2})^{\frac{\sqrt2}{2}}:16^{\frac{1}{2}}}{(2^{\sqrt2-\sqrt3})^{\sqrt2+\sqrt3}}=
=\frac{8^{\frac{\sqrt2*\sqrt2}{2}}:\sqrt{16}}{2^{(\sqrt2-\sqrt3)(\sqrt2+\sqrt3)}}=
=\frac{8:4}{2^{2-3}}=\frac{2}{2^{-1}}=2^{1-(-1)}=2^{1+1}=2^2=4