Zadanie 5
a)
\frac{2\frac{1}{6}}{1\frac{4}{9}}=\frac{\frac{13}{6}}{\frac{13}{9}}=\frac{\not13^1}{\not6^2}*\frac{\not9^3}{\not13^1}=\frac{3}{2}=1\frac{1}{2}
b)
\frac{\frac{1}{2}+\frac{1}{3}}{\frac{1}{2}}=\frac{\frac{3}{6}+\frac{2}{6}}{\frac{1}{2}}=\frac{5}{\not6^3}*\not2^1=\frac{5}{3}=1\frac{2}{3}
c)
\frac{1\frac{5}{12}}{\frac{1}{2}-\frac{1}{3}}=\frac{\frac{17}{12}}{\frac{3}{6}-\frac{2}{6}}=\frac{\frac{17}{12}}{\frac{1}{6}}=\frac{17}{\not12^2}*\frac{\not6^1}{1}=\frac{17}{2}=8\frac{1}{2}
d)
\frac{2-\frac{1}{3}}{2-\frac{1}{2}}=\frac{\frac{6}{3}-\frac{1}{3}}{\frac{4}{2}-\frac{1}{2}}=\frac{\frac{5}{3}}{\frac{3}{2}}=\frac{5}{3}*\frac{2}{3}=\frac{10}{9}=1\frac{1}{9}
e)
\frac{\frac{3}{4}+\frac{1}{8}}{\frac{3}{4}-\frac{1}{8}}=\frac{\frac{6}{8}+\frac{1}{8}}{\frac{6}{8}-\frac{1}{8}}=\frac{\frac{7}{8}}{\frac{5}{8}}=\frac{7}{\not8^1}*\frac{\not8^1}{5}=\frac{7}{5}=1\frac{2}{5}
f)
\frac{\frac{1}{2}-1\frac{2}{5}}{\frac{1}{2}-1\frac{1}{5}}=\frac{0,5-1,4}{0,5-1,2}=\frac{-0,9}{-0,7}=\frac{\frac{9}{10}}{\frac{7}{10}}=\frac{9}{\not10^1}*\frac{\not10^1}{7}=\frac{9}{7}=1\frac{2}{7}
g)
\frac{2\frac{1}{4}-3\frac{1}{2}}{\frac{1}{8}+\frac{1}{2}}=\frac{\frac{9}{4}-\frac{7}{2}}{\frac{1}{8}+\frac{4}{8}}=\frac{\frac{9}{4}-\frac{14}{4}}{\frac{5}{8}}=\frac{-\frac{5}{4}}{\frac{5}{8}}=-\frac{\not5^1}{\not4^1}*\frac{\not8^2}{\not5^1}=-2
h)
\frac{3\frac{1}{2}-\not2^1*\frac{3}{\not4^2}}{1\frac{1}{2}*\frac{2}{5}-2}=\frac{\frac{7}{2}-\frac{3}{2}}{\frac{3}{\not2^1}*\frac{\not2^1}{5}-2}=\frac{\frac{4}{2}}{\frac{3}{5}-\frac{10}{5}}=\frac{2}{-\frac{7}{5}}=-2*\frac{5}{7}=-\frac{10}{7}=-1\frac{3}{7}
i)
\frac{2\frac{3}{4}:\frac{1}{7}-22}{6-(-5)}=\frac{\frac{11}{4}*\frac{7}{1}-22}{6+5}=\frac{\frac{77}{4}-\frac{88}{4}}{11}=\frac{-\frac{11}{4}}{11}=-\frac{\not11^1}{4}*\frac{1}{\not11^1}=-\frac{1}{4}