\frac{\sqrt{0,3}}{\sqrt{1,2}}=\sqrt{\frac{0,3}{1,2}}=\sqrt{\frac{3}{12}}=\sqrt{\frac{1}{4}}=\frac{1}{2}
1\frac{11}{15}:(-2,6)=\frac{26}{15}:(-\frac{26}{10})=-\frac{\not26^1}{\not15^3}*\frac{\not10^2}{\not26^1}=-\frac{2}{3}
\sqrt{1,4}*\sqrt{2\frac{6}{7}}=\sqrt{\frac{\not14^2}{\not10^1}*\frac{\not20^2}{\not7^1}}=\sqrt4=2
\frac{1}{5}:(1,75-2)=\frac{1}{5}:(-0,25)=\frac{1}{5}:(-\frac{1}{4})=\frac{1}{5}*\frac{-4}{1}=-\frac{4}{5}=-0,8
\frac{1}{4}-0,6:(-\frac{1}{2})=\frac{1}{4}-\frac{6}{\not10^5}*(-\frac{\not2^1}{1})=\frac{1}{4}-\frac{6}{5}=0,25+1,25=1,45
(\frac{3}{4})^{-2}*(\frac{1}{4})^2=(\frac{4}{3})^2*(\frac{1}{4})^2=(\frac{\not4^1}{3}*\frac{1}{\not4^1})^2=(\frac{1}{3})^2=\frac{1}{9}
-1\frac{31}{35}R , -0,8\not A , -\frac{2}{3}\not N , -0,05O , \frac{1}{9}\not N , 0,5A , 1,45\not K , \frac{9}{16}O , 2\not R , 4T
odpowiedź:
ROOT - pierwiastek