Zadanie 1
\sqrt{49}+\sqrt[3]{27}=7+3=10
Zadanie 2
(1\frac{1}{2})^2-\frac{1}{2}*(-2)^6=(\frac{3}{2})^2-2^{-1}*2^6=\frac{9}{4}-2^{-1+6}=\frac{9}{4}-2^5=\frac{9}{4}-32=\frac{9-128}{4}=-\frac{119}{4}=-29\frac{3}{4}
Zadanie 3
\sqrt3*\sqrt{27}=\sqrt{3*27}=\sqrt{81}=9
Zadanie 4
(-2)^5:(-2)^4*(-2)^2=(-2)^{5-4+2}=(-2)^{3}=-8
(\frac{2}{5})^5:(-\frac{1}{5})^5=[\frac{2}{5}:(-\frac{1}{5}]^5=[-\frac{2}{\not5^1}*\frac{\not5^1}{1})^5=(-2)^5=-32
Zadanie 5
\sqrt[3]{40}=\sqrt[3]{8*5}=\sqrt[3]{2^3}*\sqrt[3]5=2\sqrt[3]5
Zadanie 6
5*\sqrt6=\sqrt{5^2*6}=\sqrt{25*6}=\sqrt{180}
Zadanie 7
(\frac{2\sqrt6}{3})^2=\frac{4*\not6^2}{\not9^3}=\frac{8}{3}=2\frac{2}{3}