d)
(2^{\frac{1}{2}})^{\frac{3}{2}}=2^{\frac{3}{4}}=\sqrt[4]{2^3}=\sqrt[4]{8}
(\frac{1}{2})^{-\frac{3}{4}}=2^{\frac{3}{4}}=\sqrt[4]{2^3}=\sqrt[4]{8}
{(\frac{2^{\frac{1}{2}}}{2})^{-\frac{3}{2}}=(2^{\frac{1}{2}-1})^{-\frac{3}{2}}=(2^{-\frac{1}{2}})^{-\frac{3}{2}}=2^{\frac{3}{4}}=\sqrt[4]{2^3}=\sqrt[4]{8}}