(2^{\frac{\sqrt2}{2}})^{\frac{\sqrt2}{2}}*\sqrt8+24*32^{-\frac{3}{5}}=
=2^{\frac{\sqrt2}{2}*\frac{\sqrt2}{2}}*\sqrt8+24*(2^5)^{-\frac{3}{5}}=
=2^{\frac{2}{4}}*\sqrt8+24*2^{-3}=
=2^{\frac{1}{2}}*8^{\frac{1}{2}}+24*(\frac{1}{2})^3=
(2*8)^{\frac{1}{2}}+\not24^3*\frac{1}{\not8^1}=
=16^{\frac{1}{2}}+3=
=\sqrt{16}+3=
=4+3=7 odpowiedź B