c)
\frac{\sqrt[3]{25}*5^{-\frac{1}{2}}}{(\sqrt[6]{25})^2*\sqrt5*x}=(\frac{1}{5})^2*(\frac{1}{\sqrt[4]{25}})^2 założenie x\ne 0
\frac{(5^2)^{\frac{1}{3}}*5^{-\frac{1}{2}}}{((5^2)^{\frac{1}{6}})^2*5^{\frac{1}{2}}*x}=\frac{1}{5^2}*(\frac{1}{((5^2)^{\frac{1}{4}}})^2
\frac{5^{\frac{2}{3}-\frac{1}{2}}}{5^{\frac{4}{6}+\frac{1}{2}}*x}=\frac{1}{5^2}*\frac{1}{(5^{\frac{1}{2}})^2}
\frac{5^{\frac{4-3}{6}}}{5^{\frac{4+3}{6}}*x}=\frac{1}{5^2*5}
\frac{5^{\frac{1}{6}}}{5^{\frac{7}{6}}*x}=\frac{1}{5^3}
\frac{5^{\frac{1}{6}}}{5^{\frac{1}{6}}*5^{\frac{6}{6}}*x}=\frac{1}{125}
\frac{1}{5*x}=\frac{1}{125}
5x=125 \ |:5
x=25