a)
(2x-4xy):2=\frac{\not2^1(x-2xy)}{\not2^1}=x-2xy
b)
(6a-9ab+1):(-\frac{1}{3})=(6a-9ab+1)*(-3)=-18a+27ab-3
c)
(2x^2-4x-10): \frac{2}{3}=\not2^1(x^2-2x-5)*\frac{3}{\not2^1}=3(x^2-2x-5)=3x^2-6x-15
d)
\frac{12xy-20x}{4}=\frac{\not4^1(3xy-5x)}{\not4^1}=3xy-5x
e)
\frac{10a+5b-15}{-5}=\frac{-\not5^1(-10a-b+3)}{-\not5^1}=-10a-b+3
f)
{\frac{8x^2-x+36}{4}=\frac{8x^2}{4}-\frac{x}{4}+\frac{36}{4}=2x^2-\frac{1}{4}x+9=2x^2-0,25x+9}
g)
\not30^6*\frac{c^2-3c+2}{\not5^1}=6(c^2-3c+2)=6c^2-18c+12
h)
-\not4^2*\frac{3(x+1)}{\not2^1}=-2(3x+3)=-6x-6