(9^{-\frac{2}{3}})^{\frac{3}{4}}-(25^{\frac{5}{2}})^{-\frac{1}{10}}+[(\frac{3}{4})^{-1}*(\frac{2}{9})^{\frac{6}{7}}]^0:36^{-\frac{1}{2}}+\frac{1}{\sqrt5}=
=(3^2)^{-\frac{1}{2}}-(5^2)^{-\frac{1}{4}}+1:(\frac{1}{36})^{\frac{1}{2}}+\frac{1}{\sqrt5}=
=3^{-1}-5^{-\frac{1}{2}}+1:\sqrt{\frac{1}{36}}+\frac{1}{\sqrt5}=
=\frac{1}{3}-(\frac{1}{5})^{\frac{1}{2}}+1:\frac{1}{6}+\frac{1}{\sqrt5}=
=\frac{1}{3}-\sqrt{\frac{1}{5}}+1*\frac{6}{1}+\frac{1}{\sqrt5}=
=\frac{1}{3}+6-\frac{1}{\sqrt5}+\frac{1}{\sqrt5}=6\frac{1}{3}
[(\frac{3}{4})^{-1}*(\frac{2}{9})^{\frac{6}{7}}]^0=1 bo a^0=1