\frac{y}{2}+\frac{1}{3}=\frac{7}{6} mnożymy całość *2
y+\frac{1*2}{3}=\frac{7*2}{6}
$y+\frac{2}{3}=\frac{14}{6}$skracamy
y+\frac{2}{3}=\frac{7}{3}
y=\frac{7}{3}-\frac{2}{3}
y=\frac{5}{3}
y=1\frac{2}{3}
…
\frac{1}{5}(y-3)-\frac{2}{3}(y-\frac{3}{5})+\frac{1}{3}=\frac{2}{5}-\frac{1}{3}(2y-3) mnożymy całość $15
\frac{1*15}{5}(y-3)-\frac{2*15}{3}(y-\frac{3}{5})+\frac{1*15}{3}=\frac{2*15}{5}-\frac{1*15}{3}(2y-3)
\frac{15}{5}(y-3)-\frac{30}{3}(y-\frac{3}{5})+\frac{15}{3}=\frac{30}{5}-\frac{15}{3}(2y-3)
3(y-3)-10(y-\frac{3}{5})+5=6-5(2y-3)
3y-9-10y+\frac{30}{5}+5=6-10y+15
-7y-9+6+5=-10y+21
-7y+10y=21-2
3y=19
y=\frac{19}{3}=6\frac{1}{3}