a)
x^3+27=0
(-3)^3+27=0
-27+27=0
0=0
L = P
b)
\frac{1}{3}x^3=-9
\frac{1}{3}\cdot (-3)^3=-9
\frac{1}{\not3^1}\cdot (-\not27^9)=-9
1\cdot (-9)=-9
-9=-9
L = P
c)
\frac{2}{3}x^3+18=0
\frac{2}{3}\cdot(-3)^3+18=0
\frac{2}{\not3^1}\cdot(-\not27^9)+18=0
2\cdot (-9)+18=0
-18+18=0
0=0
L = P
d)
2x^3=54
2\cdot (-3)^3=54
2\cdot (-27)=54
-54\ne 54
L\ne P
Odpowiedź D