x-\frac{-\frac{x}{2}-\frac{3-x}{5}}{2}=\frac{1}{2}-\frac{(1-\frac{4-x}{2})\cdot \frac{1}{2}+x}{2}
x-\frac{1}{2}\cdot (-\frac{x}{2}-\frac{3-x}{5})=\frac{1}{2}-\frac{1}{2}\cdot [(1-\frac{4-x}{2})\cdot \frac{1}{2}+x] \ |*2 obie strony
2x+\frac{x}{2}+\frac{3+x}{5}=1-(\frac{1}{2}-\frac{4-x}{4}+x)
\frac{20x}{10}+\frac{5x}{10}+\frac{2(3+x)}{10}=1-\frac{1}{2}+\frac{4-x}{4}-x
\frac{25x+6+2x}{10}=\frac{1}{2}+\frac{4-x}{4}-x \ |*20 obie strony
2(27x+6)=10+5(4-x)-20x
54x+12=10+20-5x-20x
54x+12=30-25x
54x+25x=30-12
79x=18
x=\frac{18}{79}