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{(2,2+\frac{2}{5}):\frac{1}{2}-2\frac{1}{5}=(2,2+0,4):0,5-2,2=\frac{2,6}{0,5}-2,2=\frac{26}{5}-2,2=5,2-2,2=3}
lub
{(2,2+\frac{2}{5}):\frac{1}{2}-2\frac{1}{5}=(\frac{22}{10}+\frac{4}{10}):\frac{1}{2}-2\frac{1}{5}=\frac{26}{\not10^5}\cdot \frac{\not2^1}{1}-2\frac{1}{5}=\frac{26}{5}-\frac{11}{5}=\frac{15}{5}=3}
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33\frac{1}{3}\% \cdot 3=\frac{100}{3}\% \cdot 3 = 100\% = 1