\frac{(1+\sqrt{12})^2-(2-\sqrt3)(\sqrt3-2)}{(\sqrt8-2)(2+2\sqrt2)}
obliczenia pomocnicze
\sqrt{12}=\sqrt{4*3}=2\sqrt3
\sqrt8=\sqrt{4*2}=2\sqrt2
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=\frac{1+2\sqrt{12}+12-(2\sqrt3-4-3+2\sqrt3)}{(2\sqrt2-2)(2\sqrt2+2)}=
=\frac{13+2*2\sqrt3-(4\sqrt3-7)}{8-4}
=\frac{13+4\sqrt3-4\sqrt3+7}{4}
=\frac{20}{4}=5