a_1=-\frac{1}{3}
a_2=\frac{1}{6}
a_1*q=a_2
q=\frac{a_2}{a_1}=\frac{\frac{1}{6}}{-\frac{1}{3}}=\frac{1}{\not6^2}*(-\frac{\not3^1}{1})=-\frac{1}{2} iloraz ciągu
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S_n=a_1*\frac{1-q^n}{1-q} wzór
n=10
{S_{10}=-\frac{1}{3}*\frac{1-(-\frac{1}{2})^{10}}{1-(-\frac{1}{2})}=-\frac{1}{3}*\frac{\frac{1024}{1024}-\frac{1}{1024}}{1+\frac{1}{2}}=-\frac{1}{3}*\frac{\frac{1023}{1024}}{\frac{3}{2}}=}
=-\frac{1}{\not3^1}*\frac{\not1023^{341}}{\not1024^{512}}*\frac{\not2^1}{3}=-\frac{341}{512*3}=-\frac{341}{1536} <-- odpowiedź