Zad. 3 a)
=log_3^2-log_3\frac{1}{9}+0=
=log_3(91:\frac{1}{9})=
=log_3729=log_39^3=log_33^6=6
‘’’’’’’’’’’’’’’’'
b)
\sqrt[3]{32} * 2^5 *(\frac{1}{8})^3=
=\sqrt[3]{2^5} *2^5 * (\frac{1}{2})^9=
=2^{\frac{5}{3}} *2^5 *2^{-9}=2^{\frac{5}{3}} *2^{-4}=2^{-\frac{7}{3}}
c)
10^{12}* 8^{-3} * 25^{-6}=
=2^{12} *5^{12} *2^{-9} * 5^{-12}=2^3
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