\frac{\sqrt2+3\sqrt8-\sqrt{18}}{\sqrt2}=
6\sqrt{50} + \sqrt{32} -3 \sqrt{72}=
źródło: zbiór zadań maturalnych
\frac{\sqrt2+3\sqrt8-\sqrt{18}}{\sqrt2}=\frac{\sqrt2+3\sqrt{4*2}-\sqrt{9*2}}{\sqrt2}=
=\frac{\sqrt2+3*2\sqrt2-3\sqrt2}{\sqrt2}=\frac{\sqrt2+6\sqrt2-3\sqrt2}{\sqrt2}=\frac{5\sqrt2}{\sqrt2}=5
6\sqrt{50}+\sqrt{32}-3\sqrt{72}=6\sqrt{25*2}+\sqrt{16*2}-3\sqrt{36*2}=
=6*5\sqrt2+4\sqrt2-3*6\sqrt2=30\sqrt2+4\sqrt2-18\sqrt2=16\sqrt2