[[(0.5)^2 - \frac{5}{36}]/(\frac{1}{3})^2] +4/3\frac{1}{4} = [[\frac{1}{4}-\frac{5}{36}]/\frac{1}{9}] + \frac{4}{3\frac{1}{4}} = [[\frac{9}{36}-\frac{5}{36}]/\frac{1}{9}] + \frac{4*4}{3*1}=[\frac{4}{36}/\frac{1}{9}] + \frac{16}{3} = [\frac{1}{9}/\frac{1}{9}] + \frac{16}{3} = [\frac{1}{9}*\frac{9}{1}] + \frac{16}{3} = \frac{16}{3} = 5\frac{1}{3}