Rozwiązanie:
a)
\sqrt3*\sqrt7=\sqrt{21}
b)
\frac{\sqrt{17}}{\sqrt{34}}=\frac{\sqrt{17}}{\sqrt2*\sqrt{17}}=\frac{1}{\sqrt2}=\frac{1*\sqrt2}{\sqrt2*\sqrt2}=\frac{\sqrt2}{2}=\frac{1}{2}\sqrt2
c)
\frac{\sqrt{200}*\sqrt7}{\sqrt{28}}=\frac{10\sqrt2*\sqrt7}{2\sqrt7}=\frac{10\sqrt2*\sqrt7*\sqrt7}{2\sqrt7*\sqrt7}=\frac{10\sqrt2*7}{2*7}=5\sqrt2
d)
(\sqrt{15}*\sqrt4):\sqrt{30}=\frac{\sqrt{60}}{\sqrt{30}}=\frac{\sqrt2*\sqrt{30}}{\sqrt{30}}=\sqrt2
e)
\sqrt[3]{7}*\sqrt[3]{16}:\sqrt[3]{28}=\frac{\sqrt[3]{112}}{\sqrt[3]{28}}=\frac{\sqrt[3]4*\sqrt[3]{28}}{\sqrt[3]{28}}=\sqrt[3]{4}
f)
\frac{\sqrt[3]9*\sqrt[3]2}{\sqrt[3]3}=\frac{\sqrt[3]3*\sqrt[3]3*\sqrt[3]2}{\sqrt[3]3}=\sqrt[3]3*\sqrt[3]2=\sqrt[3]6