Zadanie Oblicz. a) 4^2 * (1/4)^2 - (1/5)^3 * 5^3 b) (1/7)^2 * 14^2 -10^5 * (1/5)^5 c) 35^2 : (-7)^2 + (-6)^3 : (-2)^3 d) (-1/9)^2 : (1/72)^2 - (-1/36)^3 : (1/108)^3
źródło: Matematyka gimnazjum 2 klasa
Zadanie a 4^2*(\frac{1}{4})^2-(\frac{1}{5})^3*5^3=\frac{4^2}{4^2}-\frac{5^3}{5^3}=1-1=0 Zadanie b (\frac{1}{7})^2*14^2-10^5*(\frac{1}{5})^5=\frac{(2*7)^2}{7^2}-\frac{(2*5)^5}{5^5}=\frac{2^2*7^2}{7^2}-\frac{2^5*5^5}{5^5}=2^2-2^5=4-32=28
Zadanie b (\frac{1}{7})^2*14^2-10^5*(\frac{1}{5})^5=\frac{(2*7)^2}{7^2}-\frac{(2*5)^5}{5^5}=\frac{2^2*7^2}{7^2}-\frac{2^5*5^5}{5^5}=2^2-2^5=4-32=28
c 35^2:(-7)^2+(-6)^3:(-2)^3=\frac{(5*7)^2}{(-7)^2}+\frac{((-2)*3)^3}{(-2)^3}=\frac{5^2*7^2}{(-7)^2}+\frac{(-2)^3*3^3}{(-2)^3}=5^2+3^3=25+27=52 d (-\frac{1}{9})^2:(\frac{1}{72})^2-(-\frac{1}{36})^3:(\frac{1}{108})^3=\frac{(8*9)^2}{(-9)^2}-\frac{(3*36)^3}{(-36)^3}=8^2-(-(3^3)=64+27=91
Zadanie d (-\frac{1}{9})^2:(\frac{1}{72})^2-(-\frac{1}{36})^3:(\frac{1}{108})^3=\frac{(8*9)^2}{(-9)^2}-\frac{(3*36)^3}{(-36)^3}=8^2-(-(3^3)=64+27=91