a)
\sqrt{0,36}=\sqrt{(0,6)^2}=0,6
\frac{\sqrt9}{\sqrt5*\sqrt5}=\frac{3}{5}=0,6
\sqrt{0,06^2}=0,06 skreślić
\sqrt{0,1}*\sqrt{3,6}=\sqrt{0,36}=\sqrt{0,6^2}=0,6
\frac{\sqrt[3]{27}}{\sqrt[3]{125}}=\frac{\sqrt[3]{3^3}}{\sqrt[3]{5^3}}=\frac{3}{5}=0,6
\sqrt{1,2}*\sqrt{0,3}=\sqrt{0,36}=0,6
b)
\frac{5}{\sqrt8}=\frac{5\sqrt8}{\sqrt8*\sqrt8}=\frac{5*\sqrt{4*2}}{8}=\frac{5*2\sqrt2}{8}=\frac{5\sqrt2}{4}
\sqrt{\frac{25}{8}}=\frac{\sqrt{25}}{\sqrt8}=\frac{5}{\sqrt{4*2}}=\frac{5}{2\sqrt2}=\frac{5\sqrt2}{2\sqrt2*\sqrt2}=\frac{5\sqrt2}{4}
\frac{\sqrt{25}}{4\sqrt2}=\frac{5*\sqrt2}{4\sqrt2*\sqrt2}=\frac{5\sqrt2}{4*2}=\frac{5\sqrt2}{8} skreślić
\sqrt{3,125}=\sqrt{\frac{25}{8}}=\frac{5}{\sqrt{4*2}}=\frac{5}{2\sqrt2}=\frac{5\sqrt2}{2\sqrt2*\sqrt2}=\frac{5\sqrt2}{2*2}=\frac{5\sqrt2}{4}
\frac{5\sqrt2}{4}
\frac{1}{4}\sqrt{50}=\frac{1}{4}*\sqrt{5^2*2}=\frac{1}{4}*5\sqrt2=\frac{5\sqrt2}{4}
c)
\frac{4}{\sqrt2}=\frac{4\sqrt2}{\sqrt2*\sqrt2}=\frac{4\sqrt2}{2}=2\sqrt2
\sqrt8=\sqrt{2^2*2}=2\sqrt2
2\sqrt2
\frac{1}{5}\sqrt{200}=\frac{1}{5}\sqrt{10^2*2}=\frac{1}{5}*10\sqrt2=2\sqrt2
\frac{\sqrt2*\sqrt8}{2}=\frac{\sqrt{16}}{2}=\frac{4}{2}=2 skreślić
0,5\sqrt{32}=0,5*\sqrt{16*2}=0,5*4\sqrt2=2\sqrt2
zadanie powtórzone
http://pracadomowa24.pl/zadanie/25223-dzialania-na-potegach-i-pierwiastkach-gimnazjum-3/