Zadanie 1
\frac{\frac{\sqrt{3^4}}{3}-(\frac{\sqrt3}{2})^{-2}}{(\frac{2}{\sqrt3})^2*(\frac{1}{\sqrt3})^{-3}}=\frac{\frac{\sqrt{(3^2)^2}}{3}-(\frac{2}{\sqrt3})^2}{\frac{4}{3}*(\sqrt3)^3}=
\frac{\frac{3^2}{3}-\frac{4}{3}}{\frac{4}{3}*\sqrt{3^3}}=\frac{3-1\frac{1}{3}}{\frac{4}{3}*3\sqrt3}=\frac{1\frac{2}{3}}{4\sqrt3}=
\frac{5}{3}*\frac{1}{4\sqrt3}=\frac{5}{12\sqrt3}=\frac{5\sqrt3}{12\sqrt3*\sqrt3}=\frac{5\sqrt3}{36}