Zadanie:
a)
2^5-(-2)^2=32+32=64
b)
(\frac{1}{3})^4+(\frac{-1}{3})^4=\frac{1^4}{3^4}+\frac{(-1)^4}{3^4}=\frac{1+1}{3^4}=\frac{2}{81}
c)
(\frac{1}{3})^2*3^3=3^{-2}*3^3=3^{-2+3}=3
d)
10^3*0,1^2=10^3*10^{-2}=10^{3-2}=10
e)
\frac{1}{3}*3^2+\frac{1}{4}*2^2=\frac{1}{3}*9+\frac{1}{4}*4=3+1=4
f)
2*0,2^3-0,2^3=2*0,008-0,008=0,016-0,008=0,008
g)
3*(\frac{1}{2})^0+8*(-\frac{1}{2})^4=3*1+8*\frac{1}{16}=3+\frac{1}{2}=3\frac{1}{2}
h)
(\frac{1}{2})^3:(\frac{1}{6})^2-(-2)^3=\frac{1}{8}:\frac{1}{36}+8=\frac{1}{8}*36+8=\frac{1}{2}*9+8=4\frac{1}{2}+8=12\frac{1}{2}
i)
(-0,1)^4*20^3-(-2)^4=0,0001*8000-16=0,8-16=-15,2
j)
(1\frac{1}{2})^3:0,5^4+7,4^0=\frac{3^3}{2^3}:\frac{5^4}{10^4}+1=\frac{3^3}{2^3}:\frac{5^4}{2^4*5^4}+1=\frac{3^3}{2^3}*2^4+1=27*2^{4-3}+1=54+1=55
k)
3^3-(-2)^2-(-3)^0=27-4-1=22
l)
(\frac{3}{5})^2-\frac{3^2}{5}+\frac{3}{5^2}=\frac{9}{25}-\frac{9}{5}+\frac{3}{25}=\frac{9-5*9+3}{25}=\frac{9-45+3}{25}=\frac{-33}{25}=-1\frac{8}{25}
Zadanie 19
2^5+2^5=2*2^5=2^{1+5}=2^6
(-3)^3*(-3)^3*(-3)^3=(-3)^3*3=(-27)*3=-81=-3^4