Zadanie 14
a – bok kradratu
r=\frac{a}{2} promień koła wpisanego w kwadrat
Pole koła > 75% pola kwadratu
\pi r^2>75\%a^2
\pi *(\frac{a}{2})^2>\frac{75}{100}a^2
\frac{\pi a^2}{4}>\frac{3a^2}{4}
|*4
\pi a^2>3a^2 |:a^2
3,14>3
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r=\frac{d}{2}=\frac{a\sqrt2}{2} promień tego koła
pole kwadratu < 75% pola koła
a^2<\frac{75}{100}\pi r^2
a^2<\frac{3}{4}\pi *(\frac{a\sqrt2}{2})^2
a^2<\frac{3}{4}\pi *\frac{2a^2}{4}
a^2<\frac{3}{4}*3,14*\frac{a^2}{2}
a^2<\frac{9,42}{8}a^2