c)
(\frac{1}{2\sqrt5-2}-\frac{1}{2\sqrt5+2})^{-\frac{1}{2}}=2
{L=(\frac{1}{2\sqrt5-2}-\frac{1}{2\sqrt5+2})^{-\frac{1}{2}}=(\frac{2\sqrt5+2-(2\sqrt5-2)}{(2\sqrt5-2)(2\sqrt5+2)})^{-\frac{1}{2}}=(\frac{2\sqrt5+2-2\sqrt5+2}{(2\sqrt5)^2-2^2})^{-\frac{1}{2}}=}
=(\frac{4}{4*5-4})^{-\frac{1}{2}}=(\frac{4}{16})^{-\frac{1}{2}}=(\frac{16}{4})^{\frac{1}{2}}=4^{\frac{1}{2}}=\sqrt{4}=2
L=P
d)
\sqrt{2\sqrt3*(\frac{1}{3\sqrt3-\sqrt2}+\frac{1}{3\sqrt3+\sqrt2}}=1\frac{1}{5}
L=\sqrt{2\sqrt3*(\frac{1}{3\sqrt3-\sqrt2}+\frac{1}{3\sqrt3+\sqrt2}}=
=\sqrt{\frac{2\sqrt3*(3\sqrt3+\sqrt2+3\sqrt3-\sqrt2)}{(3\sqrt3-\sqrt2)(3\sqrt3+2)}}=
=\sqrt{\frac{2\sqrt3*6\sqrt3}{(3\sqrt3)^2-(\sqrt2)^2}}=
=\sqrt{\frac{12*3}{9*3-2}}=\sqrt{\frac{36}{25}}=\frac{6}{5}=1\frac{1}{5}
L=P