Q=Ek
mC_w\Delta T=\frac{mv^2}{2} |*2
2mC_w\Delta T=mv^2 |:m
2C_w\Delta T=v^2
\Delta T=\frac{v^2}{2Cw}
\Delta T=\frac{(100m/s)^2}{2\cdot 447\frac{J}{kg\cdot ^\circ C}}
\Delta T=\frac{10 000 \frac{m^2}{s^2}}{894\frac{J}{kg\cdot ^\circ C}}
\Delta T \approx 11,2 ^\circ C
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WYPROWADZENIE JEDNOSTEK
\frac{m^2}{s^2}\cdot \frac {kg \cdot ^\circ C}{\frac{kg \cdot m^2}{s^2}}=\frac{m^2}{s^2}\cdot kg \cdot ^\circ C\cdot \frac{s^2}{kg\cdot m^2}=^\circ C