\frac{\sqrt{6}+\sqrt{3}}{\sqrt{2}+1}=
całość mnożymy przez \frac{\sqrt{2}-1}{\sqrt{2}-1}
\frac{(\sqrt{6}+\sqrt{3})*(\sqrt{2}-1)}{(\sqrt{2}+1)*(\sqrt{2}-1)}=\frac{\sqrt{6}*\sqrt{2}+\sqrt{3}*\sqrt{2}-\sqrt{6}-\sqrt{3}}{(\sqrt{2})^2-1^2}=\frac{\sqrt{12}+\sqrt{6}-\sqrt{6}-\sqrt{3}}{2-1}=\sqrt{4*3}-\sqrt{3}=2\sqrt{3}-\sqrt{3}=\sqrt{3}