y= \frac{x-2}{\sqrt{\sqrt2-\sqrt6x}}
dziedzina:
\sqrt{\sqrt2-\sqrt6x}>0\\\\\sqrt2-\sqrt6x>0 \\\\ -\sqrt6x>-\sqrt2 \ |:(-\sqrt2) \\\\ \frac{-\sqrt6x}{-\sqrt2}<1 \\\\ \sqrt{\frac{6}{2}}x<1 \\\\ \sqrt3x<1 \ |*\sqrt3 \\\\ 3x<\sqrt3 \ |:3 \\\\ x<\frac{\sqrt3}{3}
D: \ x \in (-\infty;\frac{\sqrt3}{3}) <-- odpowiedź