zad. 10
1+\sqrt2\approx1+1,41\approx2,4
3\sqrt2\approx3*1,41\approx4,23\approx4,2
2\sqrt3\approx2*1,73\approx3,46\approx3,5
3-\sqrt3\approx3-1,73\approx1,27\approx1,3
\sqrt2+\sqrt3\approx1,41+1,73=3,14\approx3,1
2\sqrt2+3\sqrt3\approx2*1,41+3*1.73\approx2,82+5,19\approx8,01\approx8
zad 14
a)
\sqrt{10}+2\sqrt6-3\sqrt{10}+\sqrt6=3\sqrt6-2\sqrt{10}
b)
\sqrt[3]{-3}+2\sqrt[3]9-4\sqrt[3]3-5\sqrt[3]9=\sqrt[3]{(-1)*3}-4\sqrt[3]3-3\sqrt[3]9=-1\sqrt[3]3-4\sqrt[3]3-3\sqrt[3]9=
=-5\sqrt[3]3-3\sqrt[3]9
c)
2\sqrt{11}-\sqrt[3]{-11}+7\sqrt[3]{11}-\sqrt{11}=2\sqrt{11}-(-1)\sqrt[3]{11}+7\sqrt[3]{11}-\sqrt{11}=
=2\sqrt{11}+\sqrt[3]{11}+7\sqrt[3]{11}-\sqrt{11}=\sqrt{11}+8\sqrt[3]{11}
d)
-6(\sqrt{14}-2)-\frac{4\sqrt{14}}{2}=-6\sqrt{14}+12-2\sqrt{14}=-8\sqrt{14}+12
e)
2(\sqrt{13}+\sqrt3)-4(\sqrt{13}-3)=2\sqrt{13}+2\sqrt3-4\sqrt{13}+12=-2\sqrt{13}+2\sqrt3+12
f)
-(\sqrt[3]2-2\sqrt[3]6)+3(5\sqrt[3]2-\sqrt[3]{-6})=-\sqrt[3]2+2\sqrt[3]6+15\sqrt[3]2-3\sqrt[3]{-6}=
=14\sqrt[3]2+2\sqrt[3]6+3\sqrt[3]6=14\sqrt[3]2+5\sqrt[3]6