\frac{\sqrt{48}+\sqrt{75}}{\sqrt{27}}=\frac{\sqrt{16*3}+\sqrt{25*3}}{\sqrt{9*3}}=
=\frac{4\sqrt3+5\sqrt3}{3\sqrt3}=\frac{9\sqrt3}{3\sqrt3}=3
,
\frac{\sqrt3*\sqrt6}{\sqrt2}=\frac{\sqrt3*\sqrt{3*2}}{\sqrt2}=\frac{\sqrt3*\sqrt3*\sqrt2}{\sqrt2}=3
lub II sposób
=\frac{\sqrt{18}}{\sqrt2}=\sqrt9=3