(b) \frac{(3\cdot 2^{20}+7\cdot 2^{19})\cdot 52}{(13\cdot 8^4)^2}=
=\frac{2^{19}(3\cdot 2+7\cdot 1)\cdot 13\cdot 4}{13^2 \cdot (2^3)^8}
=\frac{2^{19}\cdot 13 \cdot 13 \cdot 2^2}{13^2 \cdot 2^{24}}
=\frac{2^{19+2}\cdot \not13^2}{\not13^2\cdot 2^{24}}
=\frac{2^{21}}{2^{24}}
=2^{21-24}=2^{-3}=(\frac{1}{2})^3=\frac{1}{8}
(e) (6.25)^{-\frac{1}{2}}\cdot (0,01)^{-1}=
=(\frac{625}{100})^{-\frac{1}{2}}\cdot \frac{1}{100})^{-1}
=(\frac{100}{625})^{\frac{1}{2}}\cdot \frac{100}{1}
=\sqrt{\frac{100}{625}}\cdot 100
=\frac{10}{\not25^1}\cdot \not100^4
=10\cdot 4=40
(f)
(\frac{25}{49})^{\frac{1}{2}}\cdot (\frac{2}{7})^{-1}=\sqrt{\frac{25}{49}} \cdot \frac{7}{2}=\frac{5}{\not7^1} \cdot \frac{\not7^1}{2}=\frac{5}{2}=2,5
(h)
3\sqrt{27}\cdot 9^{-1,5}(\frac{1}{3})^{\frac{3}{4}}\cdot (\frac{1}{81})^{-2}=
3\cdot (3^3)^{\frac{1}{2}}\cdot (3^{\not2})^{-\frac{3}{\not2}}\cdot 3^{-\frac{3}{4}}\cdot 81^2
=3\cdot 3^{\frac{3}{2}}\cdot 3^{-3}\cdot 3^{-\frac{3}{4}}\cdot (3^4)^2
=3^{1+1,5-3-0.75+8}
=3^{6,75}=3^{6\frac{3}{4}}=3^6\cdot 3^{\frac{3}{4}}
=3^6\cdot \sqrt[4]{3^3}=729\sqrt[4]{27}
\approx1661,76