a)
0,5^3=(\frac{1}{2})^3=\frac{1^3}{2^3}=\frac{1}{8}=0,125
b)
(-0,4)^4=(\frac{4}{10})^4=\frac{(2^2)^4}{10^4}=\frac{2^8}{10^4}=\frac{256}{10000}=0,0256 minus do potęgi parzystej = plus
albo
(-0,4)^4=(\frac{4}{10}^4=(\frac{2}{5})^4=\frac{2^4}{5^4}=\frac{16}{625}=0,0256
c)
1,2^2=(\frac{12}{10})^2=(\frac{6}{5})^2=\frac{6^2}{5^2}=\frac{36}{25}=1\frac{11}{25}=1,44
albo
1,2^2=(\frac{12}{10})^2=\frac{12^2}{10^2}=\frac{144}{100}=1,44
d)
(-2,5)^2=(-\frac{25}{10})^2=(-\frac{5}{2})^2=\frac{25}{4}=6\frac{1}{4}=6,25
albo
(-2,5)^2=(-\frac{25}{10})^2=\frac{625}{100}=6,25
e)
(\frac{1}{3})^3=\frac{1}{3^3}=\frac{1}{27}
f)
(\frac{3}{4})^2=\frac{3^2}{4^2}=\frac{9}{16}=0,5625
g)
(\frac{2}{5})^3=\frac{2^3}{5^3}=\frac{8}{125}=0,064
h)
-(1\frac{1}{3})^2=-(\frac{4}{3})^2=-\frac{16}{9}=-1\frac{7}{9} Zwróć uwagę, że minus jest poza nawiasem.
i)
(2\frac{1}{4})^3=(\frac{9}{4})^3=((\frac{3}{2})^2)^3=(\frac{3}{2})^{2*3}=(\frac{3}{2})^6=\frac{3^6}{2^6}=\frac{729}{64}=11\frac{25}{64}
j)
(8 \frac{5}{12})^0=1, a^0=1