\frac{1}{5}[[{\frac{1}{4}[\frac{1}{3}(\frac{1}{2}x-1)-1]-1]]-1=0
\frac{1}{5}[\frac{1}{4}(\frac{1}{6}x-\frac{1}{3}-1)-1]-1=0
\frac{1}{5}[\frac{1}{4}(\frac{1}{6}x-\frac{4}{3})-1]-1=0
\frac{1}{5}(\frac{1}{24}x-\frac{4}{12})-1=0
\frac{1}{5}(\frac{1}{24}x-\frac{16}{12})-1=0
\frac{1}{5}(\frac{1}{24}x-\frac{4}{3})-1=0
\frac{1}{120}x-\frac{4}{15}-1=0
\frac{1}{120}x-\frac{19}{15}=0
\frac{1}{120}x=\frac{19}{15}
x=\frac{19}{15}*\frac{120}{1}
x=152
\frac{1}{5}[[{\frac{1}{4}[\frac{1}{3}(\frac{1}{2}x-2)-2]-2]]-2=0
\frac{1}{5}[\frac{1}{4}(\frac{1}{6}x-\frac{2}{3}-2)-2]-2=0
\frac{1}{5}[\frac{1}{4}(\frac{1}{6}x-\frac{8}{3})-2]-2=0
\frac{1}{5}(\frac{1}{24}x-\frac{8}{12}-2)-2=0
\frac{1}{5}(\frac{1}{24}x-\frac{32}{12})-2=0
\frac{1}{5}(\frac{1}{24}x-\frac{8}{3})-2=0
\frac{1}{120}x-\frac{8}{15}-1=0
\frac{1}{120}x-\frac{38}{15}=0
\frac{1}{120}x=\frac{38}{15}
x=\frac{38}{15}*\frac{120}{1}
x=304
wynik zwiększył się *2
gdy 2 zastąpimy 5 wynik będzie =152*5=760