(x-2)^2(x^2+3x-4)=(x-1)^2(x^2+3x-4)
(x-2)^2(x^2+3x-4)-(x-1)^2(x^2+3x-4)=0
(x^2+3x-4)*[(x-2)^2-(x-1)^2]=0
(x^2+4x-x-4)*[x^2-4x+4-(x^2-2x+1)]=0
[x(x+4)-(x+4)] *(x^2-4x+4-x^2+2x-1)=0
(x+4)(x-1)(-2x+3)=0
x+4=0=>x=-4
lub
x-1=0=>x=1
lub
-2x+3=0
-2x=-3/:(-2)
x=\frac{3}{2}
x_1=-4 , x_2=\frac{3}{2} , x_3=1