Zadanie 3:
d=4\sqrt{3}
\beta=30
V=\frac{1}{3}P_p*H
d=a\sqrt{2}
a\sqrt{2}=4\sqrt{3}
a=\frac{4\sqrt{3}*\sqrt{2}}{\sqrt{2}\sqrt{2}}=2\sqrt{6}
\frac{H}{ \frac{a}{2} }=\tan(30)= \frac{\sqrt{3}}{3}
H=\frac{\sqrt{3}}{3}*\frac{a}{2}=a\frac{\sqrt{3}}{6}=2\sqrt{3*2}*\frac{\sqrt{3}}{6}=\sqrt{2}
V=\frac{1}{3}*(2\sqrt{6})^2*\sqrt{2}=\frac{1}{3}*4*6*\sqrt{2}=8\sqrt{2}
P_c=P_p+P_b
P_b=4*a*h
\frac{ \frac{a}{2} }{h}=\cos(30)=\frac{\sqrt{3} }{2}
\frac{a}{2}*2=\sqrt{3}*h
h=\frac{a}{\sqrt{3}}=\frac{2\sqrt{3*2}}{\sqrt{3} }=2\sqrt{2}
P_c=(2\sqrt{6})^2+4*2\sqrt{3*2}*2\sqrt{2}=4*6+4*2*2*2*\sqrt{3}=24+32\sqrt{3}