pole kwadratu
P=a^2
twierdzenie Pitagorasa
a^2+b^2=c^2 ===> c^2=a^2+b^2
a) a=2, b=2
c^2=2^2+2^2
c=\sqrt{8}=\sqrt{4*2}
c=2\sqrt2 przeciwprostokątna
P_1=P_2=2^2=4
P_3=c^2=(2\sqrt2)^2=4*2=8
b) a=2, b=3
c^2=2^2+3^2
c^2=13
c=\sqrt{13} przeciwprostokątna
P_1=a^2=2^2=4
P_2=b^2=3^2=9
P_3=c^2=(\sqrt{13})^2=13
c) a=1, b=2
c^2=1^2+2^2
c=\sqrt5
P_1=a^2=1
P_2=b^2=2^2=4
P_3=c^2=(\sqrt5)^2=5
d) a=1, b=3
c^2=1^2+3^2=10
c=\sqrt{10}
P_1=a^2=1
P_2=b^2=3^2=9
P_3=(\sqrt{10})^2=10