d)
\frac{4+\sqrt2}{\sqrt5}=\frac{(4+\sqrt2)*\sqrt5}{\sqrt5*\sqrt5}=\frac{4\sqrt5+\sqrt{10}}{5}
e)
\frac{\sqrt4}{\sqrt{11}}=\frac{2}{\sqrt{11}}=\frac{2\sqrt{11}}{\sqrt{11}*\sqrt{11}}=\frac{2\sqrt{11}}{11}
f)
\frac{4-\sqrt8}{\sqrt8}=\frac{4-2\sqrt2}{2\sqrt2}=\frac{(4-2\sqrt2)*\sqrt2}{2\sqrt2*\sqrt2}=\frac{4\sqrt2-2\sqrt2*\sqrt2}{2*2}=\frac{4\sqrt2-2*2}{4}=\frac{4\sqrt2-4}{4}=\frac{4(\sqrt2-1)}{4}=\sqrt2-1
g)
\frac{\sqrt6+4\sqrt2}{\sqrt3}=\frac{(\sqrt6+4\sqrt2)*\sqrt3}{\sqrt3*\sqrt3}=\frac{\sqrt{18}+4\sqrt6}{3}=\frac{\sqrt{9*2}+4\sqrt6}{3}=\frac{3\sqrt2+4\sqrt6}{3}
h)
\frac{1}{\sqrt3}=\frac{\sqrt3}{\sqrt3*\sqrt3}=\frac{\sqrt3}{3}