a=2b
Kat rozwarty ma 120 stopni
Z tw. cosinusów
d_1^2=a^2+b^2-2abcos120^0
(4\sqrt3)^2=4b^2+b^2-2*2b*b(-cos60^0)
48=5b^2-4b^2*(-\frac{1}{2})
48=5b^2+2b^2
7b^2=48
b=\sqrt{\frac{48}{7}}=\frac{4\sqrt3}{\sqrt7}=\frac{4\sqrt3*\sqrt7}{7}=\frac{4\sqrt{21}}{7}
a=2b=\frac{8\sqrt{21}}{7}
sin60^0=\frac{h}{b}
h=sin60^0*\frac{4\sqrt{21}}{7}=\frac{\sqrt3}{2}*\frac{4\sqrt{21}}{7}=
h=\frac{4\sqrt{63}}{14}=\frac{2*3\sqrt7}{7}=\frac{6\sqrt7}{7}
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