a)
\frac{3^{-2}}{2^5}*\frac{2^4}{3^{-1}}=3^{-2-(-1)}*2^{4-5}=3^{-2+1}*2^{-1}=3^{-1}*\frac{1}{2}=\frac{1}{3}*\frac{1}{2}=\frac{1}{6}
b)
7^{-1}(7^2+7^0)=\frac{1}{7}(49+1)=\frac{50}{7}=7\frac{1}{7}
c)
\frac{1^{-2}+2^{-2}}{(\frac{2}{3})^{-2}+(-4)^{-1}*5+2^{-2}}=\frac{1+(\frac{1}{2})^2}{(\frac{3}{2})^2+(-\frac{1}{4})*5+(\frac{1}{2})^2}=\frac{1\frac{1}{4}}{\frac{9}{4}-\frac{5}{4}+\frac{1}{4}}=
\frac{\frac{5}{4}}{\frac{5}{4}}=1